UVA 893 – Y3K Problem: Handling Python years above 9999
I was working on a problem in UVA online judge where I needed to do a simple data addition. However, the catch was year can go beyond 9999 (which is the limit in python). Below code is the python solution for this problem. I simply divided the date-delta with (1200 years, i.e. 438291 days) and added it separately after the computation. If you have unclear areas, let me know in the comments.
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import datetime from sys import stdin div = 438291 for line in stdin: delta, d, m, y = map(int, line.split()[:4]) if d != 0: a = int(delta / div) delta3 = delta % div d_2000 = datetime.date(day=1, month=1, year=2000) d_start = datetime.date(day=d, month=m, year=y) delta2 = (d_2000 - d_start).days delta3 -= delta2 d_end = d_2000 + datetime.timedelta(days=delta3) print(d_end.day, d_end.month, d_end.year + a * 1200) else: exit(0) |
[1] Date and Time by Mask Icon from the Noun Project